Question

A ) what is the probability that an ordinary year has 53 monday?
b.what is the probability of having 53 wednesday in a leap year?

Answer 1

The probability of having 53 Mondays in an ordinary year are 1/7 and the probability of having 53 Wednesdays in a leap year are  2/7. Hope this helps and if it does, please look at my profile and its comments. ^-^

Answer 2

Answer: a) The probability of 53 Monday in ordinary year is $\bold{\frac{1}{7}}$

               b) The probability of 53 Wednesday in leap year is $\bold{\frac{2}{7}}$

a) An ordinary year has 365 days which consists of 52 weeks + 1 day. That one day can be any day from Sunday to Saturday depending upon the year.

Here S = {Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}

n(S) = 7

Let A be the occurrence of Monday and n(A) = 1

A=$\bold{\frac{n(A)}{n(S)}=\frac{1}{7}}$

b) A leap year has 366 days which consists of 52 weeks + 2 days. Those two days can be any combination of days depending upon the year.

Here S = {Sun-Mon, Mon-Tues, Tues-Wed, Wed-Thurs, Thurs-Fri, Fri-Sat, Sat-Sun}

n(S) = 7

Let A be the occurrence of Wednesday and n(A) = 2

A=$\bold{\frac{n(A)}{n(S)}=\frac{2}{7}}$