Question

A wheel of mass 1000kg and radius 1 m is rotating at the rate of 420r.p.m.What is the constant torque required to stop the wheel in 14 rotations assuming the mass to be consentrated at the rim of the wheel??

Answer 1

Hii dear,

# Answer - Torque applied = 3142 N.m in opposite direction

# Given-

m = 1000 kg

r = 1 m

ω0 = 420 rpm = 14π rad per sec

ω = 0

t = 14 sec

α = ?

# Solution-

We all know that,

ω = ω0 + αt

0 = 14π + α×14

α = -π rad/s^2

Also moment of inertia of ring,

I = mr^2

I = 1000×1×1

I = 1000 kg.m^2

Torque applied to stop the wheel

Applied torque = Iα = 1000×(-π)

Applied torque = -3142 N.m

# Hence, 3142 N.m torque applied in opposite direction of rotating wheel to stop it.

Answer 2

Answer:

torque = -3142 N/m

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