A wire elongates by L mm when a load W is hanged from it . If the wire goes over a pulley and two weights W each are hung at the two ends, then what will be the elongation of the wire in mm?
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Hi
Here is your answer,
According to Hooke's law
Modules of elasticity , E = W/A × L/l
where , L = original length of the wire
A = cross- sectional area of the wire
∴ Elongation , Δl = WL /E
On either side of the wire, tension is W and length is l/2
Δl = WL/2/AE = WL/ 2AE =l/2
∴ Total elongation in the wire = l/2 + l/2 = l
Hope it helps you !
Here is your answer,
According to Hooke's law
Modules of elasticity , E = W/A × L/l
where , L = original length of the wire
A = cross- sectional area of the wire
∴ Elongation , Δl = WL /E
On either side of the wire, tension is W and length is l/2
Δl = WL/2/AE = WL/ 2AE =l/2
∴ Total elongation in the wire = l/2 + l/2 = l
Hope it helps you !
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