a wire in the form of an equilateral triangle of area 36 root 3 square cm is straightened and then transformed into a square.find the area enclosed by the square.
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Formulas related to the question :
Given that the Area of equilateral triangle is 36√3 cm²
Area of equilateral triangle = 36√3 cm²
So, the length of side of equilateral triangle is 12 cm
Perimeter of equilateral triangle or total length of the wire = 3( side )
Perimeter of equilateral triangle or total length of the wire = 3 ( 12 ) cm
Perimeter of equilateral triangle or total length of the wire = 36 cm
Total length cant be changed whether it will be triangle of a Square.
So, perimeter of equilateral triangle = perimeter of square
= > 36 cm = 4 × side of square
= > 36 cm / 4 = side of square
= > 9 cm = side of square
Area of square = side²
Area of square = ( 9 cm )²
Area of square = 81 cm²
Given that the Area of equilateral triangle is 36√3 cm²
Area of equilateral triangle = 36√3 cm²
So, the length of side of equilateral triangle is 12 cm
Perimeter of equilateral triangle or total length of the wire = 3( side )
Perimeter of equilateral triangle or total length of the wire = 3 ( 12 ) cm
Perimeter of equilateral triangle or total length of the wire = 36 cm
Total length cant be changed whether it will be triangle of a Square.
So, perimeter of equilateral triangle = perimeter of square
= > 36 cm = 4 × side of square
= > 36 cm / 4 = side of square
= > 9 cm = side of square
Area of square = side²
Area of square = ( 9 cm )²
Area of square = 81 cm²
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