A wire is bent in the form of a square having area 992. 25 cm what will be the radius of the semicircle formed by the same wire.
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area of quare is side square
its side be
a²= 992.25 cm²
a=31.5cm
perimeter or length of wire
4× 31.5=126 cm
so f we make circle of wire its perimeter be same so
perimeter of square = circumference of circle
2πr=126
44/7×r =126
44r =126×7
r=20.04 cm
its side be
a²= 992.25 cm²
a=31.5cm
perimeter or length of wire
4× 31.5=126 cm
so f we make circle of wire its perimeter be same so
perimeter of square = circumference of circle
2πr=126
44/7×r =126
44r =126×7
r=20.04 cm
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