Question

a wire is in a shape of a square of side 15 CM if the wire is bent into a rectangle of length 22 cm find the breadth also find their area which and close more area square or the rectangle​

Answer 1

Perimeter of square = 15 x 4 = 60 cm

Since the same wire is changed to rectangle, the perimeter would be same. So,

Perimeter of rectangle = 60 cm

2(l+b) = 60

L + b = 60/2

L + b = 30

But length of the rectangle is 22 cm. So,

22 + b = 30

B = 30-22 = 8 cm

Area of square wire = (15)^2 = 225 cm^2

Area of rectangle wire = 22 x 8 = 176 cm^2

Difference = 225 - 176 = 49 cm^2


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Answer 2

Perimeter of square = 15 x 4 = 60 cm

Since the same wire is changed to rectangle, the perimeter would be same. So,

Perimeter of rectangle = 60 cm

2(l+b) = 60

L + b = 60/2

L + b = 30

But length of the rectangle is 22 cm. So,

22 + b = 30

B = 30-22 = 8 cm

Area of square wire = (15)^2 = 225 cm^2

Area of rectangle wire = 22 x 8 = 176 cm^2

Difference = 225 - 176 = 49 cm^2