a wire is in the form of a semi circle of radius 28 cm . It is straightened and bent into the form of a square . what is the lenght of the side of the square ?
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it is given that the radius of the circle is 28 CM
length of the wire = circumference of the circle
=> circumference of the circle = 2πr = ( 2×22/7×28) = 176
let the wire is bent into the form of Square of side a centimetre
perimeter of the square = 176
=> 4a=176
=> a = (176/4) = 44 cm
hence its side of the square will be 44 CM
length of the wire = circumference of the circle
=> circumference of the circle = 2πr = ( 2×22/7×28) = 176
let the wire is bent into the form of Square of side a centimetre
perimeter of the square = 176
=> 4a=176
=> a = (176/4) = 44 cm
hence its side of the square will be 44 CM
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