Question

A wire is in the shape of a square of side 10cm. If the wire
is rebent into a rectangle of length 12cm find its breadth.
Which encloses more area, the
spuare Or the rectangle​

Answer 1

Answer:

Step-by-step explanation:

Hi ,

1 ) side of the square = a = 10 cm

2 ) if the wire is bent make a rectangle

length = l = 12cm

Let the breadth = b cm

Perimeter of the rectangle =

perimeter of the square

2 ( l + b ) = 4a

l + b = 4a /2

b = 2a - l

b = ( 2 × 10 ) - 12

b = 20 -12

b = 8 cm

3 ) area of the square = a²

A1 = ( 10 )²

A1 = 100 cm² ---- ( 1 )

4 ) area of the rectangle = lb

A2 = 12 × 8

A2 = 96 cm² ------ ( 2 )

Therefore ,

Area of the square is more than

Rectangle area.

I hope this helps you.

:)

Answer 2

Answer:

Please mark me as brainliest..

Step-by-step explanation:

Side of the square = 10 cm

Length of the wire = Perimeter of the square

= 4 x side

= 4 x 10cm

= 40 cm

Length of the rectangle, l = 12 cm. Let b be the breadth of the rectangle.

Perimeter of rectangle Length of wire = 40 cm

Perimeter of the rectangle = 2 (l + b)

40 = 2 (12 + b)

(OR) 40 / 2 = 12 + b

b = 20 - 12 = 8 cm

Therefore,The breadth of the rectangle is 8 cm.

Area of the square = (side)²

= 10 cm × 10 cm = 100cm²

Area of the rectangle = l × b

= 12cm × 8cm = 96cm²

So , the square encloses more area even though its perimeter is the same as that of the rectangle.