A wire is in the shape of a square of side 10cm. If the wire
is rebent into a rectangle of length 12cm find its breadth.
Which encloses more area, the
spuare Or the rectangle
Answers
Answer:
Step-by-step explanation:
Hi ,
1 ) side of the square = a = 10 cm
2 ) if the wire is bent make a rectangle
length = l = 12cm
Let the breadth = b cm
Perimeter of the rectangle =
perimeter of the square
2 ( l + b ) = 4a
l + b = 4a /2
b = 2a - l
b = ( 2 × 10 ) - 12
b = 20 -12
b = 8 cm
3 ) area of the square = a²
A1 = ( 10 )²
A1 = 100 cm² ---- ( 1 )
4 ) area of the rectangle = lb
A2 = 12 × 8
A2 = 96 cm² ------ ( 2 )
Therefore ,
Area of the square is more than
Rectangle area.
I hope this helps you.
:)
Answer:
Please mark me as brainliest..
Step-by-step explanation:
Side of the square = 10 cm
Length of the wire = Perimeter of the square
= 4 x side
= 4 x 10cm
= 40 cm
Length of the rectangle, l = 12 cm. Let b be the breadth of the rectangle.
Perimeter of rectangle Length of wire = 40 cm
Perimeter of the rectangle = 2 (l + b)
40 = 2 (12 + b)
(OR) 40 / 2 = 12 + b
b = 20 - 12 = 8 cm
Therefore,The breadth of the rectangle is 8 cm.
Area of the square = (side)²
= 10 cm × 10 cm = 100cm²
Area of the rectangle = l × b
= 12cm × 8cm = 96cm²
So , the square encloses more area even though its perimeter is the same as that of the rectangle.