Question

a wire is in the shape of rectangle it is length is 40 cm and breadth is 22 CM if the same wire is repaired in the shape of square what will be measure of its side​

Answer 1

Answer:

=>81cm^2

Step-by-step explanation:

L=40cm

B=22cm

The perimeter of the wire = Perimeter of the rectangle = 2 (l + b) = 2 x (40 cm + 22 cm) = 2 x 62 cm = 124 cm

Then, the perimeter of the square = 124 cm

The side length of the square = (124/4) cm = 31 cm

Area of the rectangle = l x b = 40 cm x 22 cm = 880 cm^2

Area of the square = s^2 = 31 cm x 31 cm = 961 cm^2

The shape which encloses more are = Area of square - area of reactangle

=>961cm^2-880cm^2

=>81cm^2

Answer 2

L=40cm

B=22cm

The perimeter of the wire Perimeter of the rectangle-2 (Lb) 2 x (40 cm 22 cm) 2 x 62 cm 124 cm

Then, the perimeter of the square 124 cm

The side length of the square (124/4) cm

=31 cm

Area of the rectangle Ix b 40 cm x 22 cm 880 cm^2

Area of the square s^2 =31 cm x 31 cm 961 cm^2

The shape which encloses more are Area of square area of rectangle

=>961cm^2-880cm^2

=>81cm^2

Thanks