Question

a wire is in the shape of square with each side of 16.5 CM is bent in the shape of a circle find the circumference and diameter of the circle​

Answer 1

a wire is in the shape of square with each side of 16.5 CM is bent in the shape of a circle find the circumference and diameter of the circle

circumference = 2πr

$x {?}^{2} + 1 = 0$

Answer 2

Answer:

The diameter of circle so formed is 21 cm

Step-by-step explanation:

So the side of square is 16.5 cm

It is bent to form a circle

Therefore perimeter of square will be equal to circumference of circle

Perimeter of square = 4 x side

Substitute the value and you get

Perimeter of square = 4 x 16.5

                                  = 66 cm

So the circumference of circle is  66 cm   ( perimeter of square = circumference of circle )

Now the circumference of circle = πd

Substitute the values and you get

66 = 22/7 x d

d = 66 x 7/22

d = 21 cm

Therefore the diameter of circle so formed is 21 cm

Hope this will help and mark my answer as brainliest if this helped you.