Question

a wire of 10 ohm without any change in volume so that new length of wire is doubled of its original length find the new resistence of wire ​

Answer 1

Answer: 40 ohm

Explanation: Since volume is constant it implies A1L1=A2L2

-> AL=A'(2L)

-> A' = A/2

Resistance= (resistivity)(length)/(area)

-> R1/R2 = (L1/A1)/(L2/A2)

-> 10/R2 = (L/A)/(2L/(A/2))

-> R2 = 40 ohm

Answer 2

R = 40ohm....

Hope helps u.....✌️✌️✌️