A wire of 6cm radius is cut and bent so as to lie along the circumference of a hoop whose radius is 96cm.
Find the angle (in radians) substended at the centre of the hoop.
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Answer:
Circumference of wire of Radius 6 cm = 2π x 6 = 12π
Now because this wire is cut and placed along circle with a radius of 40 cm
PQ will be the length which will be acquired by this circle
it is known that the length of the arc is θ2πr/2π
now we will put the values in it
12π = θ2π x 40/2π
θ = 12π /40
θ = π/3.3 is the Answer
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