Question

a wire of length L is used to make a circular coil of n number of turns a current I passes through the coil if twice the length of wire is used to make the call with turn of same radius making same current flow through it the magnetic field at the centre of the coil will become

Answer 1

The magnetic field in a coil is calculated as B=µnI. Where µ is the permeability (physical property), n is the turn density (which is the length of the wire divided by the number of turns; n=N/L). I is the current.

If the length of the wire is doubled, and the turns have the same radius, the number of turns will also be doubled. This means that the turn density ratio will remain the same. Since the current is also the same, the magnetic field also remains the same as nothing changes in the equation.

Answer 2

Answer:

Hope it helps...

REGARDS