a wire of resistance 5 ohm is folded it's halfed to its length find the new resistance?
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1
- Answer:
- Since, volume is constant, i.e.,
- πr
- 1
- 2
-
- l
- 1
-
- =πr
- 2
- 2
-
- l
- 2
-
- ⇒(
- r
- 2
-
- r
- 1
-
-
- )
- 2
- =(
- l
- 1
-
- l
- 2
-
-
- )=(
- l
- 3l
-
- )=3
- Now,
- R
- 2
-
- R
- 1
-
-
- =
- ρ
- A
- 2
-
- l
- 2
-
-
- ρ
- A
- 1
-
- l
- 1
-
-
-
- =
- r
- 2
- 2
-
- l
- 2
-
-
- r
- l
- 2
-
- l
- 1
-
-
-
- =
- l
- 2
-
- l
- 1
-
-
- ×
- r
- 1
- 2
-
- r
- 2
- 2
-
-
- ⇒
- R
- 2
-
- R
- 1
-
-
- =
- 3
- 1
-
- ×
- 3
- 1
-
- ⇒R
- 2
-
- =9R
- 1
-
- =9×5=45Ω
- Explanation:
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