Question

Prove that 3√2 is irrational.​

Answer 1

Answer:

$\huge\star\underline{\mathtt\orange{❥a} \mathfrak\blue{n } \mathbb\purple{ Տ} \mathbb\pink{wer}}\star\:$

3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. ... So, it concludes that 3+√2 is irrational..

Answer 2

Answer:

3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. ... So, it concludes that 3+√2 is irrational

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