Question

A wire of resistance R1 is cut into five equal pieces . These five pieces of wire are then connected in parallel. If the resistance of this combination be R2 then the ratio Of R1/R2

Answer 1

When cut into 5 pieces, resistance of each part is R/5.

So, equivalent resistance of the 5 pieces when connected in parallel is, 1/R1 = 5/R + 5/R + 5/R + 5/R + 5/R

=> R1 = R/25

So, required ratio is, R : R1 = 25 : 1

Answer 2

ANSWER:

R

1

is cut into 5 pieces. Resistance if each piece =

5

R

1

When connected in parallel net resistance unit be

5

5

R

1

⇒R

2

=

25

R

1

Now,

R

2

R−1

=

25

R

1

R

1

=25

Hence, the answer is 25.

I hope it's helpful for you.......