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PQ=PR and PM is common and Both triangle have 90° so by cpct
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PQ =PR (given)
PM =PM. (common)
angle PMQ =angle PMR (right angles)
Then,
∆PMQ ~ ∆PMR. (by cpct)
I hope this will help you
. -by ABHAY
PM =PM. (common)
angle PMQ =angle PMR (right angles)
Then,
∆PMQ ~ ∆PMR. (by cpct)
I hope this will help you
. -by ABHAY
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