Question

A wire resistence is10ohm and increase its length 10% then new resistence give me solution

Answer 1

Resistance(R) = ρ(l/a) = 10ohm

(where, l= length of wire, a= area of wire, ρ(rho)= resistivity of material of the wire).

Let R' be the new resistance.

Since, R is directly proportional to l

A 10% increment in l will lead to a 10% increment in R too,

Hence R' = R + 10%R

R' = R + (10/100)R

R' = 10 + (1/10)(10)

R' = 11 ohm.

Hope i helped you!