Math, asked by Anas11111111, 1 year ago

if 11% of a number exceeds 7% of the same by 18 the number is

Answers

Answered by vanshikaaax
209
let the number = x 
11 % of the number = 11x / 100
7 % of the the number = 7x/ 100
According to the problem,
11% of a number is exceeds 7% is 18
write the above statement into equation form
11x /100 - 7x / 100 = 18
(11x - 7x ) /100 = 18
⇒ 4x / 100 = 18
⇒ x = (18 /1 ) × ( 100 / 4 ) 
after cancellation,
x = 450 
Required number = x = 450
I hope the answer was helpful to you If it was please mark it as brainlist ❤️
Answered by abhi569
74
let the number be x,

Now,

ATQ,

(11*x)/100 = (7*x)/100 + 18

11x/100 = (7x+1800)/100

As 100 is same in both, it will 1

11x = 7x + 1800

11x - 7x =1800

4x = 1800

x =1800/4

x= 450


Then,  the number is 450 


i hope this will help you

-by ABHAY
Similar questions