if 11% of a number exceeds 7% of the same by 18 the number is
Answers
Answered by
209
let the number = x
11 % of the number = 11x / 100
7 % of the the number = 7x/ 100
According to the problem,
11% of a number is exceeds 7% is 18
write the above statement into equation form
11x /100 - 7x / 100 = 18
(11x - 7x ) /100 = 18
⇒ 4x / 100 = 18
⇒ x = (18 /1 ) × ( 100 / 4 )
after cancellation,
x = 450
Required number = x = 450
I hope the answer was helpful to you If it was please mark it as brainlist ❤️
11 % of the number = 11x / 100
7 % of the the number = 7x/ 100
According to the problem,
11% of a number is exceeds 7% is 18
write the above statement into equation form
11x /100 - 7x / 100 = 18
(11x - 7x ) /100 = 18
⇒ 4x / 100 = 18
⇒ x = (18 /1 ) × ( 100 / 4 )
after cancellation,
x = 450
Required number = x = 450
I hope the answer was helpful to you If it was please mark it as brainlist ❤️
Answered by
74
let the number be x,
Now,
ATQ,
(11*x)/100 = (7*x)/100 + 18
11x/100 = (7x+1800)/100
As 100 is same in both, it will 1
11x = 7x + 1800
11x - 7x =1800
4x = 1800
x =1800/4
x= 450
Then, the number is 450
i hope this will help you
-by ABHAY
Now,
ATQ,
(11*x)/100 = (7*x)/100 + 18
11x/100 = (7x+1800)/100
As 100 is same in both, it will 1
11x = 7x + 1800
11x - 7x =1800
4x = 1800
x =1800/4
x= 450
Then, the number is 450
i hope this will help you
-by ABHAY
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