A work of 100 joule is performed in carrying a charge of –5 C from infinity to a particular point in an
electrostatic field. The potential of this point is.
(A) 100 volt (B) 5 volt (C) –20 volt (D) 20 volt
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Answer:
v = joule / coulomb
= 100 j / |-5 c |
= 100 /5
= 20 v
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