A work of 4900 joules is done on a road of mass 50 kgto liftit to a certain height. Calculate the height through which the load is lifted.
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Given,
Work= 4900 J
m=50 kg
g=-9.8 m/s^2
Since the work is against gravity, potential energy is equal to the work done.
Therefore, P.E.=4900 J
We know,
P.E.=mgh
=>4900=50×(-9.8)h
=>h=4900/{(-9.8)×50}=4900/(-490)
=-10
Therefore height= 10 m
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