Question

A work of 98000J is done on a load of mass 100kg to lift to a certain height. Calculate the height through which it is lifted? (g=9.8m/s2)                            
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Answer 1

Given :

Work done = 98000J

Mass of the object = 100 kg

Gravitational field = 9.8 m/s²

To find :

The height through which it is lifted

Solution :

Potential energy is energy due to position.

• Potential energy is scalar quantity having magnitude.
• Sl unit of P.E is Joules.
• CGS unit of P.E is erg.

Potential energy of an object is given by

P.E = mgh

where,

• P.E denotes potential energy.
• m denotes mass.
• g denotes gravitational field.
• h denotes height.

Substituting all the given values in the formula,

➠ P.E = mgh

➠ 98000 = (100)(9.8)(h)

➠ 98000 = 980h

➠ h = 98000/980

➠ h = 100 m${.}$

thus, the height through which it is lifted is 100m.

Answer 2

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• Potential energy is energy due to position.
• Potential energy is scalar quantity having magnitude.
• Sl unit of P.E is Joules.
• CGS unit of P.E is erg.
• Potential energy of an object is given by
• P.E = mgh
• where,
• P.E denotes potential energy.
• m denotes mass.
• g denotes gravitational field.
• h denotes height.

Substituting all the given values in the formula,

➠ P.E = mgh

➠ 98000 = (100)(9.8)(h)

➠ 98000 = 980h

➠ h = 98000/980

➠ h = 100 m{.}.

thus, the height through which it is lifted is 100m.