Question

a work twice as b. if both of them can together finish a piece of work in 12days then b alone can do it in​

Answer 1

Step-by-step explanation:

A works twice as fast as B. A and B finish a job in 12 days, working together.

Let A take x days to do the work, alone. So he does (1/x)th of the work in a day.

Then B take 2x days to do the work, alone. So he does (1/2x)th of the work in a day.

A do B together do (1/x)+(1/2x) = (1/12), or

3/2x = 1/12, r

2x = 36, or

x = 18

So A does the work in 18 days while B does the same work in 36 days, each working alone.

Check: (1/18)+(1/36) = (3/36) = 1/12. Correct

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