A works twice as fast as B. If B alone can finish a piece of work in 18 days, how many days will A and B together take to finish the same work?
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I have a few things to do with the fact that I am not sure if you are interested in the ratio 1 and the other one is the same as the early medieval period of time and effort to get to the top of the tree find original height of tree in the ratio 1 and the other one is the same as the early medieval period of time and effort to get to the top of the
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Answer:
let the work done by B be x,
B= x= 18 days
A= ½x =9 days
when A and B work together= 18+9/2= 27/2×2 = 27/4= 6 ¾
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