a(x^2+1)=x(a^2+1) by quadratic formula
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Given, a(x + 1) - x(a + 1)
= ax + a - xa - x
= ax - xa - x + a
= ax(x - a) - 1(x - a)
= (x - a)*(ax - 1)
To find roots, we have to equate (x - a) = 0 and (ax - 1) = 0
So, x - a = 0 and ax - 1 = 0
=> x = a, ax = 1
=> x = a, 1/a
So, the roots are a and 1/a
= ax + a - xa - x
= ax - xa - x + a
= ax(x - a) - 1(x - a)
= (x - a)*(ax - 1)
To find roots, we have to equate (x - a) = 0 and (ax - 1) = 0
So, x - a = 0 and ax - 1 = 0
=> x = a, ax = 1
=> x = a, 1/a
So, the roots are a and 1/a
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30
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