Question

A(x,2), B(-3,4) and C(7,-5) are collinear. Find the value of x​

Answer 1

Answer:

Given points are A(x,2)B(−3,−4)C(7,−5)

(x  1 ,y 1 )=(x,2),

(x2 ,y 2 )=(−3,−4)

(x 3 ,y 3 )=(7,−5)

Step-by-step explanation:

x  1  [y  2 −y  3 ]+x2 [y  3 −y  1 ]+x  3 [y  1 −y  2 ]=0

x[(−4)−(−5)]+(−3)[(−5)−2]+7[2−(−4)]=0

x(−4+5)−3(−5−2)+7(2+4)=0

x(1)−3(−7)+7(6)=0

x+21+42=0

x+63=0

x=−63

∴ The value of x is −63.

hope it will help u...