Question

a/x-b/y=0
abb/x+aab/y=aa+bb​

Answer 1

Step-by-step explanation:

Given, a/x=b/y

Given,

=> ab^2/x + a^2b/y = a^2 + b^2

=> ab^2/x + a^2 × a/x = a^2 + b^2

=> a/x (a^2 + b^2) = a^3 + b^2

After comparing the values we get :

x=a

y=b