Physics, asked by Anonymous, 1 year ago

A young man of mass 60 kg stands on the floor of a lift which is accelerating downwards at 1m/s2, then the
reaction of the floor of the lift on the man is : (g=9.8m/s2)

Plz help ☹️☹️♥️♥️✌️

Answers

Answered by arpit582

Answer:

a young man of mass 60 kg stand from the from live on the great onwards only student reaction floor lift on the map is to be calculated

Answered by arshbbcommander

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Formula: R=m(g-a)

where m is mass

g is 9.8m/s²

a is acceleration of

When lift is moving downwards

Reaction= m(g - a)

= 60 kg × (9.8 - 1) m/s²

= 528 N

Thus he will face 528 N reaction force.

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...Hope it helps....

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