a²+1/a²=7 find the value of (a+1/a)²
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©a^2 + 1/a^2 = 7
( a )^2+( 1/ a )^2 + 2 (a) (1 /a )-2(a )(1/a)=7
(a + 1/a )^2 - 2 (a ) ( 1/ a) = 7
( a + 1 / a )^2 - 2 = 7
(a + 1/ a )^2 = 7 + 2
(a + 1 / a )^2 = 9
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Your Answer: 9
__________________________
( a )^2+( 1/ a )^2 + 2 (a) (1 /a )-2(a )(1/a)=7
(a + 1/a )^2 - 2 (a ) ( 1/ a) = 7
( a + 1 / a )^2 - 2 = 7
(a + 1/ a )^2 = 7 + 2
(a + 1 / a )^2 = 9
__________________________
Your Answer: 9
__________________________
Answered by
0
Answer:
9
Step-by-step explanation:
We can write a² +1/a² as
a² +(1/a)² + 2.a.1/a - 2.a.1/a= 7
[a² +(1/a)² + 2.a.1/a] - 2.a.1/a= 7
(a +1/a)² -2.a.1/a =7
(a +1/a)² -2 =7
(a +1/a)² =7+2=9
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