Cómo resolver {3x-4y=13 2x+3y=3
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x-4y=13
multiplying by 3 9x-12y=39....................(1)
2x+3y=3
multiplying by 4 8x+12y=12....................(2)
adding 1 and 2
17x=51
so x=51/17 =>3
substituting in 3x-4y=13 and solving -4y=4 and so y=-1
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