a2+b2+c2=14 then ab+bc+ac
bharat9291:
question is incomplete .give the value of a+b+c
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(a + b + c)^2 = (a^2 + b^2 + c^2)(2ab + 2bc + 2ca)
Given: a^2 + b^2 + c^2 = 14
(a + b + c)^2 = 14*2(ab + bc + ca)
14*2(ab + bc + ca) = (a + b + c)^2
(ab + bc + ca) = (a + b + c)^2/14*2
(ab + bc + ca) = (a + b + c)^2/28
Therefore value of ab + bc + ca = (a + b + c)^2/28
Hope it helps :)
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