Question

a³+ 8b³+ 64c³–24abc .....factorise .don't use google ,pls​

Answer 1

Answer:

a³+8b³+64c³-24abc

(a)³+(2b)³+(4c)³-3(a)(2b)(4c)

using a³+b³+c³-3abc=(a +b +c)(a²+b²+c²-ab-bc-ac)

(a+2b+4c)(a²+4b²+16c²-2ab-8bc-4ac)