English, asked by karanshama, 1 year ago

(a3+b3 +c3-3abc) /a2+b2+c2-ab-bc-ca)

Answers

Answered by sairambandari
7
Hey mate!

Here is yr answer.....



= a³+b³+c³ -3abc / (a²+b²+c²-ab-bc-ac)

= (a+b+c)(a²+b²+c²-ab-bc-ac)/a²+b²+c²-ab-bc-ca

= a+b+c


Hope it helps....


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