Question

a³+b³+c³, find the answer now.​

Answer 1

Step-by-step explanation:

a³ + b³ + c³ -3abc = ( a + b + c)(a² + b² + c² - ab - bc - ca) .

EXPAND FORM.

Answer 2

Answer:

$</p><p>How do I find the value of [math]a³ + b³ + c³ + d³[/math] if [math]a, b, c, d[/math] are the roots of equation, [math]x⁴ — 3x + 1[/math]?</p><p></p><p>,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,</p><p></p><p>Let [math] y=x^3 [/math] ; Convert the given equation to [math] 4[/math]th degree equation in y to get the result.</p><p></p><p>[math]xy-3x+1=0 \implies x=\dfrac 1 {3-y}[/math]</p><p></p><p>Substituting [math]\dfrac 1 {(3-y)^4}-\dfrac 3 {3-y}+1=0[/math]</p><p></p><p>Rearranging [math](3-y)^4-3(3-y)^3+1=0[/math]</p><p></p><p>We need only coefficients of [math]y^4[/math] and [math]y^3[/math].</p><p></p><p>Expansion gives</p><p></p><p>[math]y^4–9y^3 +………..=0[/math]</p><p></p><p>By Vieta’s rule [math]a³ + b³ + c³ + d³=\boxed{9}[/math]</p><p></p><p>536 views</p><p></p><p>View 4 Upvoters</p><p></p><p>Related Questions (More Answers Below)</p><p></p><p></p><p>$