Question

(a4-b4) is divided by a2- ab

Answer 1

it is not possible to divide it more it is divide one more step only where I leave

Answer 2

The value of $\dfrac{a^4-b^4}{a^2-b^2}=a^2+b^2$

Step-by-step explanation:

We have,

$\dfrac{a^4-b^4}{a^2-b^2}$

To find, the value of $\dfrac{a^4-b^4}{a^2-b^2}=?$

∴ $\dfrac{a^4-b^4}{a^2-b^2}$

$=\dfrac{(a^2)^2-(b^2)^2}{a^2-b^2}$

Using the algebraic identity,

$x^{2}-y^{2}=(x+y)(x-y)$

$=\dfrac{(a^2+b^2)(a^2-b^2)}{a^2-b^2}$

$=a^2+b^2$

Hence, the value of $\dfrac{a^4-b^4}{a^2-b^2}=a^2+b^2$