Question

A5 m 50 cm high vertical pole casts a shadow 3 m 20 m long, find at the same time
(i) the length of the shadow casts by another pole 10 m 50 cm nigh
(ii) the height of a pole which casts a shadow 5 m long.​

Answer 1

Explanation:

Let x m be the length of the pole whose shadow is of length 10m50cm.

Let y m be the length of the pole whose shadow is 5m long.

Clearly, it is a case of direct variation. 

i) 3.205.60=x10.50

x=5.6010.50×3.20=6

Hence, the length of the shadow is 6m. 

ii) 3.205.60=5y

x=3.205.60×5=8.75

Hence, the length of the pole is 8.75 meters.

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