Question

AABC is isosceles with AB=AC=7.5 cm and BC=9 cm (Fig 11.26). The height
AD from A to BC, is 6 cm. Find the area of AABC. What will be the height from C
to AB i.e., CE?​

Answer 1

Step-by-step explanation:

Finding area of AABC

Using BC as base and AD as height

Here,

Base = BC = 9 cm

Height = AD = 6 cm

area of ABC =1/2X BASE X HIGHT

1/2x9x6

=27cm^2

now.

Ec=?

AB =BASE

THEREFORE

area of ABC =1/2 x7.5x ec

27 x2/7.5cm2= Ec

36/5=ec

ec =7.2cm

so. EC =7.2 CM

area of abs 27 cm2

Answer 2

Answer:

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Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM