AandB together can do a piece of work in15 days ;bandc together can do it in 12days;c and a can do it in 20 days . how long will they take to finish the work , working together ? also find the number of days taken by each to do the same work , working alone.
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Answer:
TOTAL NUMBER OF DAYS TAKEN BY A, B, C ARE 10 DAYS!!!
Step-by-step explanation:
NUMBER OF DAYS TAKEN BY A AND B = 15 DAYS
NUMBER OF DAYS TAKEN BY B AND C = 12 DAYS
NUMBER OF DAYS TAKEN BY A AND C = 20 DAYS
SO,
EFFICIENCY OF A AND B = 1/15
EFFICIENCY OF B AND C = 1/12
EFFICIENCY OF A AND C = 1/20
SO,
TOTAL DAYS TAKEN =
A+B+B+C+C+A = (1/15)+(1/12)+(1/20)
2(A+B+C) = [(1*4)/15*4]+[(1*5)/(12*5)]+[(1*3)/(20*3)]
2(A+B+C) = 12/60
A+B+C = 12/(60*2)
A+B+C = 1/10
SO,
NUMBER OF DAYS TAKEN BY A,B,C = 10 DAYS
I HOPE YOU UNDERSTOOD THE QUESTION!!!
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