Question

ab =8cm m is midpoint of ab semicircle are drawn on ab taking am and mb as.... Help please

Answer 1

Let centres of semicircles on AM and BM be P and Q respectively.

AP = MQ = 8/4= 2cm = r

MP = AP = r

Let radius of big circle = R = 8/2 = 4 cm

Let radius to be found be x

CM = R-x

CQ = x+r

As circle with centre C touches the semicircles dividing the big semicircle in two equal parts and tangent CM is drawn, CM is perpendicular to AB.

Therefore, according to Pythagoras Theorem,

CQ² = MQ² + CM²

(x+r)² = r² + (R-x)²

x²+r²+2xr = r²+R²+x²-2Rx

2xr = R²-2Rx

2x(2) = 4²-2(4)x

4x = 16-8x

4x+8x = 16

12x = 16

x = 16/12

x = 4/3 cm


Hope it helps

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Answer 2

Step-by-step explanation:

here you go thank you