Math, asked by Morey4814, 1 year ago

Ab & dc are parallel sides of trapezium and & angle adc is 90. Given ab=15, cd=40 & diagnol ac=41. Calculate area of trapezium abcd

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Answered by bagi

1

AC = root of (1681-1600)= 9
area of ABCD = 9*(40+15)/2= 9*55/2= 495/2=247.5

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