AB and CD are parallel sides of trapezium ABCD. diagonals AC and BD intersect at O .prove that area of triangle AOD=area of triangle BOC
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the triangle BOC is sides
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We know that triangle between same base and lie between the same parallel are equal in area
ar(ACD)=ar(BDC)
ar(AOD)+ar(DOC)=ar(BOC)+ar(DOC)
ar(AOD)=ar(BOC)
ar(ACD)=ar(BDC)
ar(AOD)+ar(DOC)=ar(BOC)+ar(DOC)
ar(AOD)=ar(BOC)
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