Question

AB is a line segment and line L is its perpendicular bisector. If a point P lies on l , show that P is equidistant from A and B.​

Answer 1

Step-by-step explanation:

Given, PO perpendicular to AB, such that AO = BO.

PROVE THAT : PA = PB.

TO PROOF :

By the congruence of the ∆ method,,,

IN ∆AOP AND ∆POB,,

(1) PO = PO (COMMON SIDE).

(2) ANGLE POA = ANGLE POB. (BOTH OF THEM ARE 90°).

(3) AO = BO (GIVEN).

∆AOP CONGRUENT TO ∆POB (BY RHS CONGRUENCE).

PA=PB (BY CPCT).

CPCT : congruence part of congruent ∆.

HENCE PROVED!!..

HOPE ITS WILL BE HELPFUL