ABC is a right-angled triangle in which angle A is 90 degree and AB=AC.Find angle B and angle C.
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Consider ΔABC where A is right angled,
It is given that AB = AC
We know that angles opposite of equal sides are also equal, Hence ∠B = ∠C
Let ∠B be equal to x
According to the Angle Sum Property of Triangles, ∠A + ∠B + ∠C = 180°
Substituting the angles,
90° + x + x = 180° (∠B = ∠C = x)
90° + 2x = 180°
x = 45°
∴ ∠B = ∠C = 45°
It is given that AB = AC
We know that angles opposite of equal sides are also equal, Hence ∠B = ∠C
Let ∠B be equal to x
According to the Angle Sum Property of Triangles, ∠A + ∠B + ∠C = 180°
Substituting the angles,
90° + x + x = 180° (∠B = ∠C = x)
90° + 2x = 180°
x = 45°
∴ ∠B = ∠C = 45°
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