Math, asked by arbindpathak1208, 3 months ago

ABC is a right angled triangle right angled at B such that BC = 6cm and ABcm. a cirle with centre O is inscribed in triangle ABC. The radius of the circle is​

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Answered by mkprasanna15
0

Answer:

Let ABC be the right angled triangle such that ∠B = 90° , BC = 6 cm, AB = 8 cm. Let O be the centre and r be the radius of the in circle.

AB, BC and CA are tangents to the circle at P, N and M.

∴ OP = ON = OM = r (radius of the circle)

By Pythagoras theorem,

CA2 = AB2 + BC2

⇒ CA2 = 82 + 62

⇒ CA2 = 100

⇒ CA = 10 cm

Area of ∆ABC = Area ∆OAB + Area ∆OBC + Area ∆OCA

Step-by-step explanation:

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