ABC is a right angled triangle with BAC=90 .AH is drawn perpendicular to BC. If AB =60 AND AC=80cm then find the length of BH.
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We use Pythagoras theorem to get the length BC.
a2+b2=c2
(6400+3600)^1/2=100cm
Since AH cuts BC at a right angle then it means that it bisects angle BAC such that angle BAH=CAH=45°
Taking triangle ABH a right angle, we use the sin to get BH.
BH=60Sin45
60×0.7071=42.43cm
a2+b2=c2
(6400+3600)^1/2=100cm
Since AH cuts BC at a right angle then it means that it bisects angle BAC such that angle BAH=CAH=45°
Taking triangle ABH a right angle, we use the sin to get BH.
BH=60Sin45
60×0.7071=42.43cm
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