Question

ABC is a triangle in which angle B=2angleC. D is a point on BC such that AD bisect angle BAC and AB=CD.prove that angle BAC=72°




Pls help me. it's urgent

Answer 1

Step-by-step explanation:

Triangle ABC and ADC are similar (two sides and one angle is equal)

So ∠ CAD = ∠ ACB = C

∠BAC = 2c

And in triangle ABC ∠BAC + ∠ABC + ∠ACB

= 2c+2c+c

= 5c

= 180c

= 180/5

= 36

∠BAC = 2c

= 2x36

= 72

Proved .How it helps you..Mark as Brainliest