ABC is a triangle in which DE || BC. find angle A
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DE || BC
angle DEB = angle EBC (alternate interior angles)
angle DEB = 30°
angle EDB + angle ADE = 180° (linear pair)
angle ADE = (180-105)° = 75°
Similarly,
angle CEB + angle DEB + angle AED = 180°
angle AED = 70°
In triangle ADE , by A.S.P. of triangle , we have
angle A = 180° - angle ADE - angle AED
= 180° - 145°
= 35°
Hence , measure of angle A is 35°
Answered by
0
Answer:
A=35°
Step-by-step explanation:
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