Question

ABC is a triangle in which DE || BC. find angle A​

Answer 1

DE || BC

angle DEB = angle EBC (alternate interior angles)

angle DEB = 30°

angle EDB + angle ADE = 180° (linear pair)

angle ADE = (180-105)° = 75°

Similarly,

angle CEB + angle DEB + angle AED = 180°

angle AED = 70°

In triangle ADE , by A.S.P. of triangle , we have

angle A = 180° - angle ADE - angle AED

= 180° - 145°

= 35°

Hence , measure of angle A is 35°

Answer 2

Answer:

A=35°

Step-by-step explanation:

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