Abc is an equilateral triangle .Point p is on base bc such that pc=1\3 bc if ab=6cm find ap
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Answer:
5.3
Step-by-step explanation:
assume an equilateral triangle
if base is ab is 6 then bc is also 6, point between bc is 1/3 of bc or 1/3 of 6,
thus it is 2 from p to c..
consider the triangle bap..with the interior angle at b equal to 60 degree
use now the cosine law..in which
line ap^2= 4^2+6^2-2(4)(6)cos60
then ap or the required length is 2square root of 7
or 5.29
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