abc is an isoscale triangle in which ab =ac side ba is produced to d such that ad =ab show that bcd is a right angle
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this is the right way to prove
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∠b=∠acb=∠1
2∠1=∠dac
let ∠dac=∠4
and,
∠d=∠acd=∠2
2∠2=∠bac
let∠bac=∠3
in Δabc.
∠3+2∠1=180°
2∠2+2∠1=180°
∠1+∠2=90°
inΔdac,
∠4+2∠2=180°
2∠1+2∠2=180°
∠1+∠2=90°
∠bcd=∠1+∠2=90°
∴∠bcd=90°
also,∠bcd is a right angle.
i think it help you
THANK YOU :) :)
2∠1=∠dac
let ∠dac=∠4
and,
∠d=∠acd=∠2
2∠2=∠bac
let∠bac=∠3
in Δabc.
∠3+2∠1=180°
2∠2+2∠1=180°
∠1+∠2=90°
inΔdac,
∠4+2∠2=180°
2∠1+2∠2=180°
∠1+∠2=90°
∠bcd=∠1+∠2=90°
∴∠bcd=90°
also,∠bcd is a right angle.
i think it help you
THANK YOU :) :)
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