Question

Abc is an isosceles triangle in which ab=ac and d is a point on ac

Answer 1

what is your question

Answer 2

Step by step:-

Given:In ∆abc, ab=ac and d is a point on ac,such that bc=ac×ad.

=>bc/ad=ac/bc - [equation (1)]

Now,in ∆abc and ∆bdc,bc/cd=ac/bc

angle.c=angle.c (common)

=>∆abc~∆bdc ( by SAS rule)

=> ab/bd=bc/cd=ac/bc

(since ∆s are similar,corresponding sides are proportional)

=>ac/bc=bc/cd - [equation (2)]

from (1) and (2), we get

ac/bc=ac/bd

=>bc=bd.

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